Grade 12 Euclidean Geometry • Theorem 5

The Proportion Theorem

The Intuition (Plain English)

If you draw a line straight across a triangle so that it is perfectly parallel to the base, it will slice the left side and the right side in exactly the same ratio. If it cuts the left side exactly in half, it will also cut the right side exactly in half. If it cuts the left side into a 1:3 ratio, the right side is also cut into a 1:3 ratio.

The Formal Proof

This is the first of the major Grade 12 proofs. It is a classic "Area" proof, heavily relying on the fact that triangles with the same height and base have the same area.

📐 [Insert GeoGebra Diagram] Triangle ABC. Line DE || BC, intersecting AB at D and AC at E.

Given: ΔABC with line DE drawn parallel to BC, intersecting AB at D and AC at E.

R.T.P: AD/DB = AE/EC

Construction: Draw altitudes h (from E to AD) and k (from D to AE). Join BE and CD.

Statement Reason
1. Area ΔADE / Area ΔBDE = (½ · AD · h) / (½ · DB · h) = AD/DB same height h
2. Area ΔADE / Area ΔCDE = (½ · AE · k) / (½ · EC · k) = AE/EC same height k
3. But Area ΔBDE = Area ΔCDE same base DE and same height (DE ∥ BC)
4. ∴ Area ΔADE / Area ΔBDE = Area ΔADE / Area ΔCDE from 3
5. ∴ AD/DB = AE/EC from 1 and 2

How to apply this in an exam

In Paper 2, you are often given ratios (like 3:2) instead of actual lengths. You must assign a variable (like k or x) to the lengths so you don't confuse ratios for absolute cm values.

Typical Exam Question:
In ΔPQR, S lies on PQ and T lies on PR such that ST ∥ QR. Given that PS/SQ = 3/5 and PR = 32 cm, calculate the length of PT.

Step-by-Step Solution:

  1. Apply the proportion theorem:
    PT/TR = PS/SQ (line || one side of ∆)
  2. Substitute the known ratio:
    PT/TR = 3/5
  3. This means the total ratio parts for PR is 3 + 5 = 8 parts.
  4. Therefore, PT makes up 3/8 of the total length of PR.
  5. PT = 3/8 × 32
    PT = 12 cm.

⚠️ Common Exam Traps